tan(A)= 5/12 ,b=3

解答

tan (A) = \frac{5}{12}, b = 3

A \in R 无解

求解步骤

tan (A) = \frac{5}{12}, b = 3

使用反三角函数性质

tan (A) = \frac{5}{12}

tan (A) = \frac{5}{12}

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

A = arctan (\frac{5}{12}) + πn

A = arctan (\frac{5}{12}) + πn

在

b = 3

范围内的解

A \in R 无解

4 cos^{2} (x) - 5 cos (x) - 6 = 0

3 sec^{2} (\frac{x}{2}) - 4 sec (\frac{x}{2}) - 4 = 0

tan (x) = \frac{3}{10 cos ( x )}, 0^{\circ} < x < 9 0^{\circ}

2 cos^{2} (x) - 3 cos (x) = 0, 0, 2 π

2 cos^{2} (x) - 5 sin (x) = 4