es

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(3x)= 1/2 ,x=(17pi)/4

Solución

2 cos (3 x) = \frac{1}{2}, x = \frac{17 π}{4}

Solución

Sin soluci \overset{o}{ˊ} n para x \in R

Pasos de solución

2 cos (3 x) = \frac{1}{2}, x = \frac{17 π}{4}

Dividir ambos lados entre

2

2 cos (3 x) = \frac{1}{2}

Dividir ambos lados entre

2

\frac{2 cos ( 3 x )}{2} = \frac{\frac{1}{2}}{2}

Simplificar

\frac{2 cos ( 3 x )}{2} = \frac{\frac{1}{2}}{2}

Simplificar

\frac{2 cos ( 3 x )}{2} : cos (3 x)

\frac{2 cos ( 3 x )}{2}

Dividir:

\frac{2}{2} = 1

= cos (3 x)

Simplificar

\frac{\frac{1}{2}}{2} : \frac{1}{4}

\frac{\frac{1}{2}}{2}

Aplicar las propiedades de las fracciones:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{1}{2 \cdot 2}

Multiplicar los numeros:

2 \cdot 2 = 4

= \frac{1}{4}

cos (3 x) = \frac{1}{4}

cos (3 x) = \frac{1}{4}

cos (3 x) = \frac{1}{4}

Aplicar propiedades trigonométricas inversas

cos (3 x) = \frac{1}{4}

Soluciones generales para

cos (3 x) = \frac{1}{4}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

3 x = arccos (\frac{1}{4}) + 2 πn, 3 x = 2 π - arccos (\frac{1}{4}) + 2 πn

3 x = arccos (\frac{1}{4}) + 2 πn, 3 x = 2 π - arccos (\frac{1}{4}) + 2 πn

Resolver

3 x = arccos (\frac{1}{4}) + 2 πn : x = \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

3 x = arccos (\frac{1}{4}) + 2 πn

Dividir ambos lados entre

3

3 x = arccos (\frac{1}{4}) + 2 πn

Dividir ambos lados entre

3

\frac{3 x}{3} = \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

Simplificar

x = \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

x = \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

Resolver

3 x = 2 π - arccos (\frac{1}{4}) + 2 πn : x = \frac{2 π}{3} - \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

3 x = 2 π - arccos (\frac{1}{4}) + 2 πn

Dividir ambos lados entre

3

3 x = 2 π - arccos (\frac{1}{4}) + 2 πn

Dividir ambos lados entre

3

\frac{3 x}{3} = \frac{2 π}{3} - \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

Simplificar

x = \frac{2 π}{3} - \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

x = \frac{2 π}{3} - \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

x = \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}, x = \frac{2 π}{3} - \frac{arccos ( \frac{1}{4} )}{3} + \frac{2 πn}{3}

Soluciones para el rango

x = \frac{17 π}{4}

Sin soluci \overset{o}{ˊ} n para x \in R

Ejemplos populares

cos(θ)=sin(36)

cos (θ) = sin (3 6^{\circ})

2sec^2(x)=tan^2(x)+2sec(x)+4

2 sec^{2} (x) = tan^{2} (x) + 2 sec (x) + 4

cos^2(θ)+sin(θ)+1=0

cos^{2} (θ) + sin (θ) + 1 = 0

cos(x)=(22.5)/(34)

cos (x) = \frac{22.5}{34}

tan (x) = - \frac{6}{7}