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人気のある三角関数 >

(1+csc(γ))/(cot(γ)+cos(γ))=csc(γ)

解

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} = csc (γ)

解

γ = \frac{π}{4} + πn

+1

度

γ = 4 5^{\circ} + 18 0^{\circ} n

解答ステップ

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} = csc (γ)

両辺から

csc (γ)

を引く

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} - csc (γ) = 0

簡素化

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} - csc (γ) : \frac{1 + csc ( γ ) - csc ( γ ) ( cot ( γ ) + cos ( γ ) )}{cot ( γ ) + cos ( γ )}

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} - csc (γ)

元を分数に変換する:

csc (γ) = \frac{csc ( γ ) ( cot ( γ ) + cos ( γ ) )}{cot ( γ ) + cos ( γ )}

= \frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} - \frac{csc ( γ ) ( cot ( γ ) + cos ( γ ) )}{cot ( γ ) + cos ( γ )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + csc ( γ ) - csc ( γ ) ( cot ( γ ) + cos ( γ ) )}{cot ( γ ) + cos ( γ )}

\frac{1 + csc ( γ ) - csc ( γ ) ( cot ( γ ) + cos ( γ ) )}{cot ( γ ) + cos ( γ )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 + csc (γ) - csc (γ) (cot (γ) + cos (γ)) = 0

サイン, コサインで表わす

1 + csc (γ) - (cos (γ) + cot (γ)) csc (γ)

基本的な三角関数の公式を使用する:

csc (x) = \frac{1}{sin ( x )}

= 1 + \frac{1}{sin ( γ )} - (cos (γ) + cot (γ)) \frac{1}{sin ( γ )}

基本的な三角関数の公式を使用する:

cot (x) = \frac{cos ( x )}{sin ( x )}

= 1 + \frac{1}{sin ( γ )} - (cos (γ) + \frac{cos ( γ )}{sin ( γ )}) \frac{1}{sin ( γ )}

簡素化

1 + \frac{1}{sin ( γ )} - (cos (γ) + \frac{cos ( γ )}{sin ( γ )}) \frac{1}{sin ( γ )} : \frac{sin ^{2} ( γ ) + sin ( γ ) - cos ( γ ) sin ( γ ) - cos ( γ )}{sin ^{2} ( γ )}

1 + \frac{1}{sin ( γ )} - (cos (γ) + \frac{cos ( γ )}{sin ( γ )}) \frac{1}{sin ( γ )}

(cos (γ) + \frac{cos ( γ )}{sin ( γ )}) \frac{1}{sin ( γ )} = \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ^{2} ( γ )}

(cos (γ) + \frac{cos ( γ )}{sin ( γ )}) \frac{1}{sin ( γ )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( cos ( γ ) + \frac{c o s ( γ )}{s i n ( γ )} )}{sin ( γ )}

1 \cdot (cos (γ) + \frac{cos ( γ )}{sin ( γ )}) = cos (γ) + \frac{cos ( γ )}{sin ( γ )}

1 \cdot (cos (γ) + \frac{cos ( γ )}{sin ( γ )})

乗算:

1 \cdot (cos (γ) + \frac{cos ( γ )}{sin ( γ )}) = (cos (γ) + \frac{cos ( γ )}{sin ( γ )})

= (cos (γ) + \frac{cos ( γ )}{sin ( γ )})

括弧を削除する:

(a) = a

= cos (γ) + \frac{cos ( γ )}{sin ( γ )}

= \frac{cos ( γ ) + \frac{c o s ( γ )}{s i n ( γ )}}{sin ( γ )}

結合

cos (γ) + \frac{cos ( γ )}{sin ( γ )} : \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ( γ )}

cos (γ) + \frac{cos ( γ )}{sin ( γ )}

元を分数に変換する:

cos (γ) = \frac{cos ( γ ) sin ( γ )}{sin ( γ )}

= \frac{cos ( γ ) sin ( γ )}{sin ( γ )} + \frac{cos ( γ )}{sin ( γ )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ( γ )}

= \frac{\frac{c o s ( γ ) s i n ( γ ) + c o s ( γ )}{s i n ( γ )}}{sin ( γ )}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ( γ ) sin ( γ )}

sin (γ) sin (γ) = sin^{2} (γ)

sin (γ) sin (γ)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

sin (γ) sin (γ) = sin^{1 + 1} (γ)

= sin^{1 + 1} (γ)

数を足す:

1 + 1 = 2

= sin^{2} (γ)

= \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ^{2} ( γ )}

= 1 + \frac{1}{sin ( γ )} - \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ^{2} ( γ )}

元を分数に変換する:

1 = \frac{1}{1}

= \frac{1}{1} + \frac{1}{sin ( γ )} - \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ^{2} ( γ )}

以下の最小公倍数:

1, sin (γ), sin^{2} (γ) : sin^{2} (γ)

1, sin (γ), sin^{2} (γ)

最小公倍数 (LCM)

因数分解された式の 1 つ以上に合わられる因数で構成された式を計算する

= sin^{2} (γ)

LCMに基づいて分数を調整する

該当する分母を乗じてLCMに変えるために

必要な量で各分子を乗じる

sin^{2} (γ)

\frac{1}{1}

の場合

:

分母と分子に以下を乗じる:

sin^{2} (γ)

\frac{1}{1} = \frac{1 \cdot sin ^{2} ( γ )}{1 \cdot sin ^{2} ( γ )} = \frac{sin ^{2} ( γ )}{sin ^{2} ( γ )}

\frac{1}{sin ( γ )}

の場合

:

分母と分子に以下を乗じる:

sin (γ)

\frac{1}{sin ( γ )} = \frac{1 \cdot sin ( γ )}{sin ( γ ) sin ( γ )} = \frac{sin ( γ )}{sin ^{2} ( γ )}

= \frac{sin ^{2} ( γ )}{sin ^{2} ( γ )} + \frac{sin ( γ )}{sin ^{2} ( γ )} - \frac{cos ( γ ) sin ( γ ) + cos ( γ )}{sin ^{2} ( γ )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ^{2} ( γ ) + sin ( γ ) - ( cos ( γ ) sin ( γ ) + cos ( γ ) )}{sin ^{2} ( γ )}

- (cos (γ) sin (γ) + cos (γ)) : - cos (γ) sin (γ) - cos (γ)

- (cos (γ) sin (γ) + cos (γ))

括弧を分配する

= - (cos (γ) sin (γ)) - (cos (γ))

マイナス・プラスの規則を適用する

+ (- a) = - a

= - cos (γ) sin (γ) - cos (γ)

= \frac{sin ^{2} ( γ ) + sin ( γ ) - cos ( γ ) sin ( γ ) - cos ( γ )}{sin ^{2} ( γ )}

= \frac{sin ^{2} ( γ ) + sin ( γ ) - cos ( γ ) sin ( γ ) - cos ( γ )}{sin ^{2} ( γ )}

\frac{- cos ( γ ) + sin ( γ ) + sin ^{2} ( γ ) - cos ( γ ) sin ( γ )}{sin ^{2} ( γ )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- cos (γ) + sin (γ) + sin^{2} (γ) - cos (γ) sin (γ) = 0

因数

- cos (γ) + sin (γ) + sin^{2} (γ) - cos (γ) sin (γ) : (1 + sin (γ)) (- cos (γ) + sin (γ))

- cos (γ) + sin (γ) + sin^{2} (γ) - cos (γ) sin (γ)

共通項をくくり出す

cos (γ)

= - cos (γ) (1 + sin (γ)) + sin (γ) + sin^{2} (γ)

指数の規則を適用する:

a^{b + c} = a^{b} a^{c}

sin^{2} (γ) = sin (γ) sin (γ)

= - cos (γ) (1 + sin (γ)) + sin (γ) + sin (γ) sin (γ)

共通項をくくり出す

sin (γ)

= - cos (γ) (1 + sin (γ)) + sin (γ) (1 + sin (γ))

共通項をくくり出す

(1 + sin (γ))

= (1 + sin (γ)) (- cos (γ) + sin (γ))

(1 + sin (γ)) (- cos (γ) + sin (γ)) = 0

各部分を別個に解く

1 + sin (γ) = 0 or - cos (γ) + sin (γ) = 0

1 + sin (γ) = 0 : γ = \frac{3 π}{2} + 2 πn

1 + sin (γ) = 0

1

を右側に移動します

1 + sin (γ) = 0

両辺から

1

を引く

1 + sin (γ) - 1 = 0 - 1

簡素化

sin (γ) = - 1

sin (γ) = - 1

以下の一般解

sin (γ) = - 1

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

γ = \frac{3 π}{2} + 2 πn

γ = \frac{3 π}{2} + 2 πn

- cos (γ) + sin (γ) = 0 : γ = \frac{π}{4} + πn

- cos (γ) + sin (γ) = 0

三角関数の公式を使用して書き換える

- cos (γ) + sin (γ) = 0

cos (γ), cos (γ) \neq = 0

で両辺を割る

\frac{- cos ( γ ) + sin ( γ )}{cos ( γ )} = \frac{0}{cos ( γ )}

簡素化

- 1 + \frac{sin ( γ )}{cos ( γ )} = 0

基本的な三角関数の公式を使用する:

\frac{sin ( x )}{cos ( x )} = tan (x)

- 1 + tan (γ) = 0

- 1 + tan (γ) = 0

1

を右側に移動します

- 1 + tan (γ) = 0

両辺に

1

を足す

- 1 + tan (γ) + 1 = 0 + 1

簡素化

tan (γ) = 1

tan (γ) = 1

以下の一般解

tan (γ) = 1

tan (x)

πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

γ = \frac{π}{4} + πn

γ = \frac{π}{4} + πn

すべての解を組み合わせる

γ = \frac{3 π}{2} + 2 πn, γ = \frac{π}{4} + πn

equationは以下で未定義のため:

\frac{3 π}{2} + 2 πn

γ = \frac{π}{4} + πn

グラフ

人気の例

sin (θ) = \frac{2}{6}

3 sin (2 x) = - 2

solvefor x,arctan(y)=2arctan(x)

so l v e f or x, arctan (y) = 2 arctan (x)

sin(2x)=-sqrt(3/2)

sin (2 x) = - \frac{3}{2}

tan(x)=(7.3)/(6.8)

tan (x) = \frac{7.3}{6.8}