zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

7tan(x)=2sqrt(3)+tan(x),0<= θ<= 90

解答

7 tan (x) = 23 + tan (x), 0^{\circ} \leq θ \leq 9 0^{\circ}

解答

x = 3 0^{\circ}

+1

弧度

x = \frac{π}{6}

求解步骤

7 tan (x) = 23 + tan (x), 0^{\circ} \leq θ \leq 9 0^{\circ}

用替代法求解

7 tan (x) = 23 + tan (x)

令

: tan (x) = u

7 u = 23 + u

7 u = 23 + u : u = \frac{3}{3}

7 u = 23 + u

将

u

para o lado esquerdo

7 u = 23 + u

两边减去

u

7 u - u = 23 + u - u

化简

6 u = 23

6 u = 23

两边除以

6

6 u = 23

两边除以

6

\frac{6 u}{6} = \frac{2 3}{6}

化简

u = \frac{3}{3}

u = \frac{3}{3}

u = tan (x)

代回

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}, 0 \leq θ \leq 9 0^{\circ} : x = 3 0^{\circ}

tan (x) = \frac{3}{3}, 0 \leq θ \leq 9 0^{\circ}

tan (x) = \frac{3}{3}

的通解

tan (x)

周期表（周期为

18 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = 3 0^{\circ} + 18 0^{\circ} n

x = 3 0^{\circ} + 18 0^{\circ} n

在

0 \leq θ \leq 9 0^{\circ}

范围内的解

x = 3 0^{\circ}

合并所有解

x = 3 0^{\circ}

作图

流行的例子

sin (X) = 1

solvefor x,(17)/(sin(x))=(23)/(sin(75))

so l v e f or x, \frac{17}{sin ( x )} = \frac{23}{sin ( 7 5 ^{\circ} )}

3-2cos^2(x)=4sin^2(x)

3 - 2 cos^{2} (x) = 4 sin^{2} (x)

4-4cos(2x)-3sin(x)=0

4 - 4 cos (2 x) - 3 sin (x) = 0

2sin^2(w)+sin(w)-1=0

2 sin^{2} (w) + sin (w) - 1 = 0