solvefor θ,w=fdcos(θ)

Lösung

löse nach

θ, w = fd cos (θ)

θ = arccos (\frac{w}{fd}) + 2 πn, θ = - arccos (\frac{w}{fd}) + 2 πn

Schritte zur Lösung

w = fd cos (θ)

Tausche die Seiten

fd cos (θ) = w

Teile beide Seiten durch

fd; fd \neq = 0

fd cos (θ) = w

Teile beide Seiten durch

fd; fd \neq = 0

\frac{fd cos ( θ )}{fd} = \frac{w}{fd}; fd \neq = 0

Vereinfache

cos (θ) = \frac{w}{fd}; fd \neq = 0

cos (θ) = \frac{w}{fd}; fd \neq = 0

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{w}{fd}

Allgemeine Lösung für

cos (θ) = \frac{w}{fd}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

θ = arccos (\frac{w}{fd}) + 2 πn, θ = - arccos (\frac{w}{fd}) + 2 πn

θ = arccos (\frac{w}{fd}) + 2 πn, θ = - arccos (\frac{w}{fd}) + 2 πn

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