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Beliebt Trigonometrie >

(2sin(x)-cos(x))(1+cos(x))=sin^2(x)

Lösung

(2 sin (x) - cos (x)) (1 + cos (x)) = sin^{2} (x)

Lösung

x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Grad

x = 18 0^{\circ} + 36 0^{\circ} n, x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

(2 sin (x) - cos (x)) (1 + cos (x)) = sin^{2} (x)

Subtrahiere

sin^{2} (x)

von beiden Seiten

(2 sin (x) - cos (x)) (1 + cos (x)) - sin^{2} (x) = 0

Umschreiben mit Hilfe von Trigonometrie-Identitäten

- sin^{2} (x) + (- cos (x) + 2 sin (x)) (1 + cos (x))

Verwende die Pythagoreische Identität:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= - (1 - cos^{2} (x)) + (- cos (x) + 2 sin (x)) (1 + cos (x))

Vereinfache

- (1 - cos^{2} (x)) + (- cos (x) + 2 sin (x)) (1 + cos (x)) : - cos (x) + 2 sin (x) + 2 sin (x) cos (x) - 1

- (1 - cos^{2} (x)) + (- cos (x) + 2 sin (x)) (1 + cos (x))

- (1 - cos^{2} (x)) : - 1 + cos^{2} (x)

- (1 - cos^{2} (x))

Setze Klammern

= - (1) - (- cos^{2} (x))

Wende Minus-Plus Regeln an

- (- a) = a, - (a) = - a

= - 1 + cos^{2} (x)

= - 1 + cos^{2} (x) + (- cos (x) + 2 sin (x)) (1 + cos (x))

Multipliziere aus

(- cos (x) + 2 sin (x)) (1 + cos (x)) : - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x)

(- cos (x) + 2 sin (x)) (1 + cos (x))

Wende Ausklammerungsregel an (VANI):

(a + b) (c + d) = a c + a d + b c + b d

a = - cos (x), b = 2 sin (x), c = 1, d = cos (x)

= (- cos (x)) \cdot 1 + (- cos (x)) cos (x) + 2 sin (x) \cdot 1 + 2 sin (x) cos (x)

Wende Minus-Plus Regeln an

+ (- a) = - a

= - 1 \cdot cos (x) - cos (x) cos (x) + 2 \cdot 1 \cdot sin (x) + 2 sin (x) cos (x)

Vereinfache

- 1 \cdot cos (x) - cos (x) cos (x) + 2 \cdot 1 \cdot sin (x) + 2 sin (x) cos (x) : - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x)

- 1 \cdot cos (x) - cos (x) cos (x) + 2 \cdot 1 \cdot sin (x) + 2 sin (x) cos (x)

1 \cdot cos (x) = cos (x)

1 \cdot cos (x)

Multipliziere:

1 \cdot cos (x) = cos (x)

= cos (x)

cos (x) cos (x) = cos^{2} (x)

cos (x) cos (x)

Wende Exponentenregel an:

a^{b} \cdot a^{c} = a^{b + c}

cos (x) cos (x) = cos^{1 + 1} (x)

= cos^{1 + 1} (x)

Addiere die Zahlen:

1 + 1 = 2

= cos^{2} (x)

2 \cdot 1 \cdot sin (x) = 2 sin (x)

2 \cdot 1 \cdot sin (x)

Multipliziere die Zahlen:

2 \cdot 1 = 2

= 2 sin (x)

= - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x)

= - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x)

= - 1 + cos^{2} (x) - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x)

Vereinfache

- 1 + cos^{2} (x) - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x) : - cos (x) + 2 sin (x) + 2 sin (x) cos (x) - 1

- 1 + cos^{2} (x) - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x)

Fasse gleiche Terme zusammen

= cos^{2} (x) - cos (x) - cos^{2} (x) + 2 sin (x) + 2 sin (x) cos (x) - 1

Addiere gleiche Elemente:

cos^{2} (x) - cos^{2} (x) = 0

= - cos (x) + 2 sin (x) + 2 sin (x) cos (x) - 1

= - cos (x) + 2 sin (x) + 2 sin (x) cos (x) - 1

= - cos (x) + 2 sin (x) + 2 sin (x) cos (x) - 1

- 1 - cos (x) + 2 sin (x) + 2 cos (x) sin (x) = 0

Faktorisiere

- 1 - cos (x) + 2 sin (x) + 2 cos (x) sin (x) : (cos (x) + 1) (2 sin (x) - 1)

- 1 - cos (x) + 2 sin (x) + 2 cos (x) sin (x)

= (- cos (x) - 1) + (2 sin (x) cos (x) + 2 sin (x))

Klammere

2 sin (x)

aus

2 sin (x) cos (x) + 2 sin (x)

aus

: 2 sin (x) (cos (x) + 1)

2 sin (x) cos (x) + 2 sin (x)

Klammere gleiche Terme aus

2 sin (x)

= 2 sin (x) (cos (x) + 1)

Klammere

- 1

aus

- cos (x) - 1

aus

: - (cos (x) + 1)

- cos (x) - 1

Klammere gleiche Terme aus

- 1

= - (cos (x) + 1)

= 2 sin (x) (cos (x) + 1) - (cos (x) + 1)

Klammere gleiche Terme aus

cos (x) + 1

= (cos (x) + 1) (2 sin (x) - 1)

(cos (x) + 1) (2 sin (x) - 1) = 0

Löse jeden Teil einzeln

cos (x) + 1 = 0 or 2 sin (x) - 1 = 0

cos (x) + 1 = 0 : x = π + 2 πn

cos (x) + 1 = 0

Verschiebe

1

auf die rechte Seite

cos (x) + 1 = 0

Subtrahiere

1

von beiden Seiten

cos (x) + 1 - 1 = 0 - 1

Vereinfache

cos (x) = - 1

cos (x) = - 1

Allgemeine Lösung für

cos (x) = - 1

cos (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

2 sin (x) - 1 = 0 : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

2 sin (x) - 1 = 0

Verschiebe

1

auf die rechte Seite

2 sin (x) - 1 = 0

Füge

1

zu beiden Seiten hinzu

2 sin (x) - 1 + 1 = 0 + 1

Vereinfache

2 sin (x) = 1

2 sin (x) = 1

Teile beide Seiten durch

2

2 sin (x) = 1

Teile beide Seiten durch

2

\frac{2 sin ( x )}{2} = \frac{1}{2}

Vereinfache

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2}

Allgemeine Lösung für

sin (x) = \frac{1}{2}

sin (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Kombiniere alle Lösungen

x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Graph

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10 cos^{2} (x) + cos (x) = 11 sin^{2} (x) - 9

sin(6.5x+2.5)=0.0851

sin (6.5 x + 2.5) = 0.0851