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受欢迎的三角函数 >

tan^2(b)=3

解答

tan^{2} (b) = 3

解答

b = \frac{π}{3} + πn, b = \frac{2 π}{3} + πn

+1

度数

b = 6 0^{\circ} + 18 0^{\circ} n, b = 12 0^{\circ} + 18 0^{\circ} n

求解步骤

tan^{2} (b) = 3

用替代法求解

tan^{2} (b) = 3

令

: tan (b) = u

u^{2} = 3

u^{2} = 3 : u = 3, u = - 3

u^{2} = 3

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

u = 3, u = - 3

u = tan (b)

代回

tan (b) = 3, tan (b) = - 3

tan (b) = 3, tan (b) = - 3

tan (b) = 3 : b = \frac{π}{3} + πn

tan (b) = 3

tan (b) = 3

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

b = \frac{π}{3} + πn

b = \frac{π}{3} + πn

tan (b) = - 3 : b = \frac{2 π}{3} + πn

tan (b) = - 3

tan (b) = - 3

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

b = \frac{2 π}{3} + πn

b = \frac{2 π}{3} + πn

合并所有解

b = \frac{π}{3} + πn, b = \frac{2 π}{3} + πn

作图

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