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sin^2(x)cos^2(x)=((1-cos^4(x)))/8

Solución

sin^{2} (x) cos^{2} (x) = \frac{( 1 - cos ^{4} ( x ) )}{8}

Solución

x = 1.18319 \dots + 2 πn, x = 2 π - 1.18319 \dots + 2 πn, x = 1.95839 \dots + 2 πn, x = - 1.95839 \dots + 2 πn, x = 2 πn, x = π + 2 πn

Grados

x = 67.79234 \dots^{\circ} + 36 0^{\circ} n, x = 292.20765 \dots^{\circ} + 36 0^{\circ} n, x = 112.20765 \dots^{\circ} + 36 0^{\circ} n, x = - 112.20765 \dots^{\circ} + 36 0^{\circ} n, x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Pasos de solución

sin^{2} (x) cos^{2} (x) = \frac{( 1 - cos ^{4} ( x ) )}{8}

Restar

\frac{1 - cos ^{4} ( x )}{8}

de ambos lados

sin^{2} (x) cos^{2} (x) - \frac{1 - cos ^{4} ( x )}{8} = 0

Simplificar

sin^{2} (x) cos^{2} (x) - \frac{1 - cos ^{4} ( x )}{8} : \frac{8 sin ^{2} ( x ) cos ^{2} ( x ) - 1 + cos ^{4} ( x )}{8}

sin^{2} (x) cos^{2} (x) - \frac{1 - cos ^{4} ( x )}{8}

Convertir a fracción:

sin^{2} (x) cos^{2} (x) = \frac{sin ^{2} ( x ) cos ^{2} ( x ) 8}{8}

= \frac{sin ^{2} ( x ) cos ^{2} ( x ) \cdot 8}{8} - \frac{1 - cos ^{4} ( x )}{8}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ^{2} ( x ) cos ^{2} ( x ) \cdot 8 - ( 1 - cos ^{4} ( x ) )}{8}

Expandir

sin^{2} (x) cos^{2} (x) \cdot 8 - (1 - cos^{4} (x)) : sin^{2} (x) cos^{2} (x) \cdot 8 - 1 + cos^{4} (x)

sin^{2} (x) cos^{2} (x) \cdot 8 - (1 - cos^{4} (x))

= 8 sin^{2} (x) cos^{2} (x) - (1 - cos^{4} (x))

- (1 - cos^{4} (x)) : - 1 + cos^{4} (x)

- (1 - cos^{4} (x))

Poner los parentesis

= - (1) - (- cos^{4} (x))

Aplicar las reglas de los signos

- (- a) = a, - (a) = - a

= - 1 + cos^{4} (x)

= sin^{2} (x) cos^{2} (x) \cdot 8 - 1 + cos^{4} (x)

= \frac{8 sin ^{2} ( x ) cos ^{2} ( x ) - 1 + cos ^{4} ( x )}{8}

\frac{8 sin ^{2} ( x ) cos ^{2} ( x ) - 1 + cos ^{4} ( x )}{8} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

8 sin^{2} (x) cos^{2} (x) - 1 + cos^{4} (x) = 0

Re-escribir usando identidades trigonométricas

- 1 + cos^{4} (x) + 8 cos^{2} (x) sin^{2} (x)

Utilizar la identidad pitagórica:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= - 1 + cos^{4} (x) + 8 cos^{2} (x) (1 - cos^{2} (x))

Simplificar

- 1 + cos^{4} (x) + 8 cos^{2} (x) (1 - cos^{2} (x)) : - 7 cos^{4} (x) + 8 cos^{2} (x) - 1

- 1 + cos^{4} (x) + 8 cos^{2} (x) (1 - cos^{2} (x))

Expandir

8 cos^{2} (x) (1 - cos^{2} (x)) : 8 cos^{2} (x) - 8 cos^{4} (x)

8 cos^{2} (x) (1 - cos^{2} (x))

Poner los parentesis utilizando:

a (b - c) = ab - a c

a = 8 cos^{2} (x), b = 1, c = cos^{2} (x)

= 8 cos^{2} (x) \cdot 1 - 8 cos^{2} (x) cos^{2} (x)

= 8 \cdot 1 \cdot cos^{2} (x) - 8 cos^{2} (x) cos^{2} (x)

Simplificar

8 \cdot 1 \cdot cos^{2} (x) - 8 cos^{2} (x) cos^{2} (x) : 8 cos^{2} (x) - 8 cos^{4} (x)

8 \cdot 1 \cdot cos^{2} (x) - 8 cos^{2} (x) cos^{2} (x)

8 \cdot 1 \cdot cos^{2} (x) = 8 cos^{2} (x)

8 \cdot 1 \cdot cos^{2} (x)

Multiplicar los numeros:

8 \cdot 1 = 8

= 8 cos^{2} (x)

8 cos^{2} (x) cos^{2} (x) = 8 cos^{4} (x)

8 cos^{2} (x) cos^{2} (x)

Aplicar las leyes de los exponentes:

a^{b} \cdot a^{c} = a^{b + c}

cos^{2} (x) cos^{2} (x) = cos^{2 + 2} (x)

= 8 cos^{2 + 2} (x)

Sumar:

2 + 2 = 4

= 8 cos^{4} (x)

= 8 cos^{2} (x) - 8 cos^{4} (x)

= 8 cos^{2} (x) - 8 cos^{4} (x)

= - 1 + cos^{4} (x) + 8 cos^{2} (x) - 8 cos^{4} (x)

Simplificar

- 1 + cos^{4} (x) + 8 cos^{2} (x) - 8 cos^{4} (x) : - 7 cos^{4} (x) + 8 cos^{2} (x) - 1

- 1 + cos^{4} (x) + 8 cos^{2} (x) - 8 cos^{4} (x)

Agrupar términos semejantes

= cos^{4} (x) + 8 cos^{2} (x) - 8 cos^{4} (x) - 1

Sumar elementos similares:

cos^{4} (x) - 8 cos^{4} (x) = - 7 cos^{4} (x)

= - 7 cos^{4} (x) + 8 cos^{2} (x) - 1

= - 7 cos^{4} (x) + 8 cos^{2} (x) - 1

= - 7 cos^{4} (x) + 8 cos^{2} (x) - 1

- 1 - 7 cos^{4} (x) + 8 cos^{2} (x) = 0

Usando el método de sustitución

- 1 - 7 cos^{4} (x) + 8 cos^{2} (x) = 0

Sea:

cos (x) = u

- 1 - 7 u^{4} + 8 u^{2} = 0

- 1 - 7 u^{4} + 8 u^{2} = 0 : u = \frac{1}{7}, u = - \frac{1}{7}, u = 1, u = - 1

- 1 - 7 u^{4} + 8 u^{2} = 0

Escribir en la forma binómica

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- 7 u^{4} + 8 u^{2} - 1 = 0

Re-escribir la ecuación con

v = u^{2}

v^{2} = u^{4}

- 7 v^{2} + 8 v - 1 = 0

Resolver

- 7 v^{2} + 8 v - 1 = 0 : v = \frac{1}{7}, v = 1

- 7 v^{2} + 8 v - 1 = 0

Resolver con la fórmula general para ecuaciones de segundo grado:

- 7 v^{2} + 8 v - 1 = 0

Formula general para ecuaciones de segundo grado:

Para

a = - 7, b = 8, c = - 1

v_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 7 ) ( - 1 )}{2 ( - 7 )}

v_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 7 ) ( - 1 )}{2 ( - 7 )}

8^{2} - 4 (- 7) (- 1) = 6

8^{2} - 4 (- 7) (- 1)

Aplicar la regla

- (- a) = a

= 8^{2} - 4 \cdot 7 \cdot 1

Multiplicar los numeros:

4 \cdot 7 \cdot 1 = 28

= 8^{2} - 28

8^{2} = 64

= 64 - 28

Restar:

64 - 28 = 36

= 36

Descomponer el número en factores primos:

36 = 6^{2}

= 6^{2}

Aplicar las leyes de los exponentes:

6^{2} = 6

= 6

v_{1, 2} = \frac{- 8 \pm 6}{2 ( - 7 )}

Separar las soluciones

v_{1} = \frac{- 8 + 6}{2 ( - 7 )}, v_{2} = \frac{- 8 - 6}{2 ( - 7 )}

v = \frac{- 8 + 6}{2 ( - 7 )} : \frac{1}{7}

\frac{- 8 + 6}{2 ( - 7 )}

Quitar los parentesis:

(- a) = - a

= \frac{- 8 + 6}{- 2 \cdot 7}

Sumar/restar lo siguiente:

- 8 + 6 = - 2

= \frac{- 2}{- 2 \cdot 7}

Multiplicar los numeros:

2 \cdot 7 = 14

= \frac{- 2}{- 14}

Aplicar las propiedades de las fracciones:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2}{14}

Eliminar los terminos comunes:

2

= \frac{1}{7}

v = \frac{- 8 - 6}{2 ( - 7 )} : 1

\frac{- 8 - 6}{2 ( - 7 )}

Quitar los parentesis:

(- a) = - a

= \frac{- 8 - 6}{- 2 \cdot 7}

Restar:

- 8 - 6 = - 14

= \frac{- 14}{- 2 \cdot 7}

Multiplicar los numeros:

2 \cdot 7 = 14

= \frac{- 14}{- 14}

Aplicar las propiedades de las fracciones:

\frac{- a}{- b} = \frac{a}{b}

= \frac{14}{14}

Aplicar la regla

\frac{a}{a} = 1

= 1

Las soluciones a la ecuación de segundo grado son:

v = \frac{1}{7}, v = 1

v = \frac{1}{7}, v = 1

Sustituir hacia atrás la

v = u^{2},

resolver para

u

Resolver

u^{2} = \frac{1}{7} : u = \frac{1}{7}, u = - \frac{1}{7}

u^{2} = \frac{1}{7}

Para

x^{2} = f (a)

las soluciones son

x = f (a), - f (a)

u = \frac{1}{7}, u = - \frac{1}{7}

Resolver

u^{2} = 1 : u = 1, u = - 1

u^{2} = 1

Para

x^{2} = f (a)

las soluciones son

x = f (a), - f (a)

u = 1, u = - 1

1 = 1

1

Aplicar la regla

1 = 1

= 1

- 1 = - 1

- 1

Aplicar la regla

1 = 1

= - 1

u = 1, u = - 1

Las soluciones son

u = \frac{1}{7}, u = - \frac{1}{7}, u = 1, u = - 1

Sustituir en la ecuación

u = cos (x)

cos (x) = \frac{1}{7}, cos (x) = - \frac{1}{7}, cos (x) = 1, cos (x) = - 1

cos (x) = \frac{1}{7}, cos (x) = - \frac{1}{7}, cos (x) = 1, cos (x) = - 1

cos (x) = \frac{1}{7} : x = arccos (\frac{1}{7}) + 2 πn, x = 2 π - arccos (\frac{1}{7}) + 2 πn

cos (x) = \frac{1}{7}

Aplicar propiedades trigonométricas inversas

cos (x) = \frac{1}{7}

Soluciones generales para

cos (x) = \frac{1}{7}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{1}{7}) + 2 πn, x = 2 π - arccos (\frac{1}{7}) + 2 πn

x = arccos (\frac{1}{7}) + 2 πn, x = 2 π - arccos (\frac{1}{7}) + 2 πn

cos (x) = - \frac{1}{7} : x = arccos (- \frac{1}{7}) + 2 πn, x = - arccos (- \frac{1}{7}) + 2 πn

cos (x) = - \frac{1}{7}

Aplicar propiedades trigonométricas inversas

cos (x) = - \frac{1}{7}

Soluciones generales para

cos (x) = - \frac{1}{7}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- \frac{1}{7}) + 2 πn, x = - arccos (- \frac{1}{7}) + 2 πn

x = arccos (- \frac{1}{7}) + 2 πn, x = - arccos (- \frac{1}{7}) + 2 πn

cos (x) = 1 : x = 2 πn

cos (x) = 1

Soluciones generales para

cos (x) = 1

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Resolver

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

cos (x) = - 1 : x = π + 2 πn

cos (x) = - 1

Soluciones generales para

cos (x) = - 1

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

Combinar toda las soluciones

x = arccos (\frac{1}{7}) + 2 πn, x = 2 π - arccos (\frac{1}{7}) + 2 πn, x = arccos (- \frac{1}{7}) + 2 πn, x = - arccos (- \frac{1}{7}) + 2 πn, x = 2 πn, x = π + 2 πn

Mostrar soluciones en forma decimal

x = 1.18319 \dots + 2 πn, x = 2 π - 1.18319 \dots + 2 πn, x = 1.95839 \dots + 2 πn, x = - 1.95839 \dots + 2 πn, x = 2 πn, x = π + 2 πn

Ejemplos populares

sin^3(x)+sin(x)=2sin^{22}(x)

sin^{3} (x) + sin (x) = 2 sin^{22} (x)

(1+tan^2(x))/(1+sec(x))=sec(x)

\frac{1 + tan ^{2} ( x )}{1 + sec ( x )} = sec (x)

-sin^2(x)+2cos(x)-2=0

- sin^{2} (x) + 2 cos (x) - 2 = 0

sin(5x-1)= 4/5

sin (5 x - 1) = \frac{4}{5}

sin^2(x)= 1/36

sin^{2} (x) = \frac{1}{36}