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Popular >

cos(x-15^0)=((sqrt(2)))/2

Solución

cos (x - 1 5^{0}) = \frac{( 2 )}{2}

Solución

x = \frac{π}{4} + 2 πn + 1, x = \frac{7 π}{4} + 2 πn + 1

+1

Grados

x = 102.29577 \dots^{\circ} + 36 0^{\circ} n, x = 372.29577 \dots^{\circ} + 36 0^{\circ} n

Pasos de solución

cos (x - 1 5^{0}) = \frac{( 2 )}{2}

Soluciones generales para

cos (x - 1 5^{0}) = \frac{2}{2}

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x - 1 5^{0} = \frac{π}{4} + 2 πn, x - 1 5^{0} = \frac{7 π}{4} + 2 πn

x - 1 5^{0} = \frac{π}{4} + 2 πn, x - 1 5^{0} = \frac{7 π}{4} + 2 πn

Resolver

x - 1 5^{0} = \frac{π}{4} + 2 πn : x = \frac{π}{4} + 2 πn + 1

x - 1 5^{0} = \frac{π}{4} + 2 πn

Aplicar la regla

a^{0} = 1, a \neq = 0

1 5^{0} = 1

x - 1 = \frac{π}{4} + 2 πn

Mover

1

al lado derecho

x - 1 = \frac{π}{4} + 2 πn

Sumar

1

a ambos lados

x - 1 + 1 = \frac{π}{4} + 2 πn + 1

Simplificar

x = \frac{π}{4} + 2 πn + 1

x = \frac{π}{4} + 2 πn + 1

Resolver

x - 1 5^{0} = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{4} + 2 πn + 1

x - 1 5^{0} = \frac{7 π}{4} + 2 πn

Aplicar la regla

a^{0} = 1, a \neq = 0

1 5^{0} = 1

x - 1 = \frac{7 π}{4} + 2 πn

Mover

1

al lado derecho

x - 1 = \frac{7 π}{4} + 2 πn

Sumar

1

a ambos lados

x - 1 + 1 = \frac{7 π}{4} + 2 πn + 1

Simplificar

x = \frac{7 π}{4} + 2 πn + 1

x = \frac{7 π}{4} + 2 πn + 1

x = \frac{π}{4} + 2 πn + 1, x = \frac{7 π}{4} + 2 πn + 1

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\frac{5}{tan ( x )} = - 2

tan^{22}(x)=sec^2(x)-1

tan^{22} (x) = sec^{2} (x) - 1