The sum of three numbers is 13. The sum of twice the first number, 3 times the second number, and 4 times the third number is 36. The difference between 6 times the first number and the second number is 40. Find the three numbers.

Solución

Solución

The numbers : 7, 2, 4

Pasos de solución

Represent the numbers with

x, y, z

number 1 : x

number 2 : y

number 3 : z

A.T.Q.:

x + y + z = 13

2 x + 3 y + 4 z = 36

6 x - y = 40

x + y + z = 13, 2 x + 3 y + 4 z = 36, 6 x - y = 40 : x = 7, y = 2, z = 4

The numbers : 7, 2, 4

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The sum of three numbers is 13. The sum of twice the first​ number, 3 times the second​ number, and 4 times the third number is 36. The difference between 6 times the first number and the second number is 40. Find the three numbers.

Solución

Solución

Ejemplos populares

The sum of three numbers is 13. The sum of twice the first number, 3 times the second number, and 4 times the third number is 36. The difference between 6 times the first number and the second number is 40. Find the three numbers.