the product of two consecutive integers is 6 times the sum of the two integers Find the two integers

解

t h e p ro d u c t o f tw o co n sec u t i v e in t e g ers i s 6 t im es t h e s u m o f t h e tw o in t e g ers F in d t h e tw o in t e g ers

The numbers : \frac{11 + 145}{2}, \frac{11 + 145}{2} + 1 or \frac{11 - 145}{2}, \frac{11 - 145}{2} + 1

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number : x + 1

A.T.Q.:

x (x + 1) = 6 (x + x + 1)

解く

x (x + 1) = 6 (x + x + 1) : x = \frac{11 + 145}{2}, x = \frac{11 - 145}{2}

挿入

x = \frac{11 + 145}{2} : \frac{11 + 145}{2} + 1

挿入

x = \frac{11 - 145}{2} : \frac{11 - 145}{2} + 1

The numbers : \frac{11 + 145}{2}, \frac{11 + 145}{2} + 1 or \frac{11 - 145}{2}, \frac{11 - 145}{2} + 1