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Popolare Word Problems >

The sum of the squares of two consecutive integers is 41 . Find the integers.

Soluzione

T h e s u m o f t h e s q u a res o f tw o co n sec u t i v e in t e g ers i s 41 . F in d t h e in t e g ers .

Soluzione

The numbers : 4, 5 or - 5, - 4

Fasi della soluzione

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} + (x + 1)^{2} = 41

Risolvi

x^{2} + (x + 1)^{2} = 41 : x = 4, x = - 5

Inserire in

x = 4 : 5

Inserire in

x = - 5 : - 4

The numbers : 4, 5 or - 5, - 4

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