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What is the probability that the three cards dealt are, in ordenar, an ace, a face card, and a 2? (A face card is a jack, queen, or king.)

Solución

What is the probability that the three cards dealt are, in order, an ace, a face card, and a 2? (A face card is a jack, queen, or king.)

Solución

\frac{1}{13}

Pasos de solución

Find the probability of getting ace face and getting 2 face jack queen :

0

Find the probability of getting 2 face jack queen :

0

Find the probability of king.:

\frac{1}{13}

Since the events are disjoint, Use the formula

P (X_{1} \lor X_{2} \lor \dots \lor X_{k}) = P (X_{1}) + P (X_{2}) + \dots + P (X_{k})

= 0 + 0 + \frac{1}{13}

Aplicar la propiedad:

a + 0 = a

= \frac{1}{13}

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the product of seventeen and the quantity of a number minus eight Find two consecutive integers such that 7 times the smaller integer is 19 more than 6 times the larger integer.the product of a number and-25 is equal to the number increased by-2 The sum of three consecutive numbers is 36 Use the formula for present value of money to calculate the amount you need to invest now in one lump sum in ordenar to have 1,000,000 after 40 years with an APR of 9% compounded quarterly. Round your answer to the nearest cent, if necessary.