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Popular >

The sum of the squares of two consecutive positive odd integers is 202. find the integers.

Solución

The sum of the squares of two consecutive positive odd integers is 202. find the integers.

Solución

The numbers : 9, 11

Pasos de solución

Represent the numbers with

x

:

First number : x

Consecutive number : x + 2

A.T.Q.:

x^{2} + (x + 2)^{2} = 202

Resolver

x^{2} + (x + 2)^{2} = 202 : x = 9, x = - 11

Select positive solutions:

9

x + 2 = 9 + 2 = 11

The numbers : 9, 11

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