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The sum of the squares of three consecutive odd integers is 363. Find the numbers

Solución

The sum of the squares of three consecutive odd integers is 363. Find the numbers

Solución

Sin soluci \overset{o}{ˊ} n

Pasos de solución

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x^{2} + (x + 2)^{2} + (x + 4)^{2} = 363

Resolver

x^{2} + (x + 2)^{2} + (x + 4)^{2} = 363 : x = \frac{- 6 + 1065}{3}, x = - \frac{6 + 1065}{3}

Sustituir

x = \frac{- 6 + 1065}{3} :

Invalido

Sustituir

x = - \frac{6 + 1065}{3} :

Invalido

Sin soluci \overset{o}{ˊ} n

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