Find three consecutive odd integers such that three times the product of the first and last integers, decreased by 150, is equal to the square of the second integer.

Solución

Solución

Sin soluci \overset{o}{ˊ} n

Pasos de solución

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

3 \dots - 150 = (x + 2)^{2}

Resolver

3 \dots - 150 = (x + 2)^{2} : x = 3 \dots - 150 - 2, x = - 3 \dots - 150 - 2

Sustituir

x = 3 \dots - 150 - 2 :

Invalido

Sustituir

x = - 3 \dots - 150 - 2 :

Invalido

Sin soluci \overset{o}{ˊ} n

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