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the sum of three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer

Solución

the sum of three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer

Solución

The numbers : - 5 \frac{2}{7}, - 3 \frac{2}{7}, - 1 \frac{2}{7}

Pasos de solución

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x + x + 2 = 3 + 9 (x + 4)

Resolver

x + x + 2 = 3 + 9 (x + 4) : x = - \frac{37}{7}

x + 2 = - \frac{37}{7} + 2 = - \frac{23}{7}

x + 4 = - \frac{37}{7} + 4 = - \frac{9}{7}

Convertir las fracciones impropias a números mixtos:

\frac{37}{7} = 5 \frac{2}{7}

Convertir las fracciones impropias a números mixtos:

\frac{23}{7} = 3 \frac{2}{7}

Convertir las fracciones impropias a números mixtos:

\frac{9}{7} = 1 \frac{2}{7}

The numbers : - 5 \frac{2}{7}, - 3 \frac{2}{7}, - 1 \frac{2}{7}

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