The sum of three integers is 37. The sum of the first and second integers exceeds the third by 45. The third integer is 20 less than the first. Find the three integers.

Solución

Solución

The numbers : 11 \frac{2}{3}, 33 \frac{2}{3}, - 8 \frac{1}{3}

Pasos de solución

Represent the numbers with

x, y, z

number 1 : x

number 2 : y

number 3 : z

A.T.Q.:

x + y + z = 37

x + y = \frac{1}{3} + 45

z = x - 20

x + y + z = 37, x + y = \frac{1}{3} + 45, z = x - 20 : x = \frac{35}{3}, y = \frac{101}{3}, z = - \frac{25}{3}

Convertir las fracciones impropias a números mixtos:

\frac{35}{3} = 11 \frac{2}{3}

Convertir las fracciones impropias a números mixtos:

\frac{101}{3} = 33 \frac{2}{3}

Convertir las fracciones impropias a números mixtos:

\frac{25}{3} = 8 \frac{1}{3}

The numbers : 11 \frac{2}{3}, 33 \frac{2}{3}, - 8 \frac{1}{3}

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