What are the solutions to the equation 2z^2+6z-20=0 ?

The solutions to the equation 2z^2+6z-20=0 are z=2,z=-5

Find the zeros of 2z^2+6z-20=0

The zeros of 2z^2+6z-20=0 are z=2,z=-5

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2 z^{2} + 6 z - 20 = 0

z = 2, z = - 5

Solution steps

2 z^{2} + 6 z - 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 20) = 14

z_{1, 2} = \frac{- 6 \pm 14}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 6 + 14}{2 \cdot 2}, z_{2} = \frac{- 6 - 14}{2 \cdot 2}

z = \frac{- 6 + 14}{2 \cdot 2} : 2

z = \frac{- 6 - 14}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

z = 2, z = - 5

1 3^{12} \cdot 1 3^{- 10}

f^{2} + 12 f + 20

- 5 + 2 x^{2} = - 6 x

5 x = - 7 x - 48

5.1 x = - 22.44

What are the solutions to the equation 2z^2+6z-20=0 ?
The solutions to the equation 2z^2+6z-20=0 are z=2,z=-5
Find the zeros of 2z^2+6z-20=0
The zeros of 2z^2+6z-20=0 are z=2,z=-5