What is factor y^6+7y^3-8 ?

The solution to factor y^6+7y^3-8 is (y-1)(y^2+y+1)(y+2)(y^2-2y+4)

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factor y^6+7y^3-8

factor

y^{6} + 7 y^{3} - 8

(y - 1) (y^{2} + y + 1) (y + 2) (y^{2} - 2 y + 4)

Solution steps

y^{6} + 7 y^{3} - 8

Use the rational root theorem

= (y - 1) \frac{y ^{6} + 7 y ^{3} - 8}{y - 1}

\frac{y ^{6} + 7 y ^{3} - 8}{y - 1} = y^{5} + y^{4} + y^{3} + 8 y^{2} + 8 y + 8

= (y - 1) (y^{5} + y^{4} + y^{3} + 8 y^{2} + 8 y + 8)

Factor

y^{5} + y^{4} + y^{3} + 8 y^{2} + 8 y + 8 : (y^{2} + y + 1) (y + 2) (y^{2} - 2 y + 2^{2})

= (y - 1) (y^{2} + y + 1) (y + 2) (y^{2} - 2 y + 2^{2})

2^{2} = 4

= (y - 1) (y^{2} + y + 1) (y + 2) (y^{2} - 2 y + 4)

\frac{2}{2 - x} \geq \frac{4}{x}

x^{3} + 5 x^{2} - x - 5

2 x^{2} + 5 x + 14 x + 35

81 y^{4} - 1

\frac{40 x ^{8} y ^{2}}{24 x ^{7} y ^{5}}

What is factor y^6+7y^3-8 ?
The solution to factor y^6+7y^3-8 is (y-1)(y^2+y+1)(y+2)(y^2-2y+4)