|x|<= 12

Lösung

∣ x ∣ \leq 12

- 12 \leq x \leq 12

Intervall-Notation

[- 12, 12]

Schritte zur Lösung

∣ x ∣ \leq 12

Wende Absoluteregel an: Wenn

∣ u ∣ \leq a, a > 0

dann

- a \leq u \leq a

- 12 \leq x \leq 12

\frac{x + 18}{x + 4} \geq 3

3 + 6 x = 2 x + 27

\frac{n}{3} - \frac{n}{5} = 2

- 176 = - 11 n

f a c t or x^{2} + 5 x y - 24 y^{2}