128^{x+3}<(1/1024)^{2x}

Lösung

12 8^{x + 3} < (\frac{1}{1024})^{2 x}

x < - \frac{7}{9}

Intervall-Notation

(- \infty, - \frac{7}{9})

Dezimale

x < - 0.77777 \dots

Schritte zur Lösung

12 8^{x + 3} < (\frac{1}{1024})^{2 x}

Wenn

f (x) < g (x)

dann

ln (f (x)) < ln (g (x))

ln (12 8^{x + 3}) < ln ((\frac{1}{1024})^{2 x})

Vereinfache

ln (12 8^{x + 3}) : 7 ln (2) (x + 3)

Vereinfache

ln ((\frac{1}{1024})^{2 x}) : - 10 ln (2) \cdot 2 x

7 ln (2) (x + 3) < - 10 ln (2) \cdot 2 x

7 ln (2) (x + 3) < - 10 ln (2) \cdot 2 x : x < - \frac{7}{9}

x < - \frac{7}{9}

4 ∣ x - 3 ∣ + 6 \leq 58

\frac{x + 4}{3} - \frac{x - 4}{5} = 2 + \frac{3 x - 1}{15}

f a c t or 2 x^{3} + 3 x^{2} - 18 x - 27

f a c t or 2 p^{2} - 5 p - 7

f a c t or w^{4} - 625