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Beliebt Algebra >

vereinfachen (25a^2b^8)^{1/2}

Lösung

vereinfachen

(25 a^{2} b^{8})^{\frac{1}{2}}

Lösung

5 a b^{4}

Schritte zur Lösung

(25 a^{2} b^{8})^{\frac{1}{2}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(25 a^{2} b^{8})^{\frac{1}{2}} = 2 5^{\frac{1}{2}} (a^{2})^{\frac{1}{2}} (b^{8})^{\frac{1}{2}}

= 2 5^{\frac{1}{2}} (a^{2})^{\frac{1}{2}} (b^{8})^{\frac{1}{2}}

2 5^{\frac{1}{2}} = 5

= 5 (a^{2})^{\frac{1}{2}} (b^{8})^{\frac{1}{2}}

Vereinfache

(a^{2})^{\frac{1}{2}} : a

= 5 a (b^{8})^{\frac{1}{2}}

Vereinfache

(b^{8})^{\frac{1}{2}} : b^{4}

= 5 a b^{4}

Beliebte Beispiele

2 x + 6 \geq 4 x

x^{2} - 16 x = 0

(x-3)^2+9(x-3)+14=0

(x - 3)^{2} + 9 (x - 3) + 14 = 0

10 - 8 t + 0.8 t^{2} = 0

faktorisieren 2x^4+12x^3-8x^2-48x

f a c t or 2 x^{4} + 12 x^{3} - 8 x^{2} - 48 x