簡約 (4x^4+3x^3+2x^2-x+1)+(5x^2-2x+3)

解

簡約

(4 x^{4} + 3 x^{3} + 2 x^{2} - x + 1) + (5 x^{2} - 2 x + 3)

4 x^{4} + 3 x^{3} + 7 x^{2} - 3 x + 4

解答ステップ

(4 x^{4} + 3 x^{3} + 2 x^{2} - x + 1) + (5 x^{2} - 2 x + 3)

簡素化

(4 x^{4} + 3 x^{3} + 2 x^{2} - x + 1) + (5 x^{2} - 2 x + 3) : 4 x^{4} + 3 x^{3} + 2 x^{2} - x + 1 + 5 x^{2} - 2 x + 3

= 4 x^{4} + 3 x^{3} + 2 x^{2} - x + 1 + 5 x^{2} - 2 x + 3

条件のようなグループ

= 4 x^{4} + 3 x^{3} + 2 x^{2} + 5 x^{2} - x - 2 x + 1 + 3

類似した元を足す:

2 x^{2} + 5 x^{2} = 7 x^{2}

= 4 x^{4} + 3 x^{3} + 7 x^{2} - x - 2 x + 1 + 3

類似した元を足す:

- x - 2 x = - 3 x

= 4 x^{4} + 3 x^{3} + 7 x^{2} - 3 x + 1 + 3

数を足す:

1 + 3 = 4

= 4 x^{4} + 3 x^{3} + 7 x^{2} - 3 x + 4