解答
化简 (1+i)25
解答
4096+4096i
求解步骤
(1+i)25
使用二项式定理: (a+b)n=i=0∑n(in)a(n−i)bia=1,b=i
=i=0∑25(i25)⋅1(25−i)ii
展开求和
=0!(25−0)!25!⋅125i0+1!(25−1)!25!⋅124i1+2!(25−2)!25!⋅123i2+3!(25−3)!25!⋅122i3+4!(25−4)!25!⋅121i4+5!(25−5)!25!⋅120i5+6!(25−6)!25!⋅119i6+7!(25−7)!25!⋅118i7+8!(25−8)!25!⋅117i8+9!(25−9)!25!⋅116i9+10!(25−10)!25!⋅115i10+11!(25−11)!25!⋅114i11+12!(25−12)!25!⋅113i12+13!(25−13)!25!⋅112i13+14!(25−14)!25!⋅111i14+15!(25−15)!25!⋅110i15+16!(25−16)!25!⋅19i16+17!(25−17)!25!⋅18i17+18!(25−18)!25!⋅17i18+19!(25−19)!25!⋅16i19+20!(25−20)!25!⋅15i20+21!(25−21)!25!⋅14i21+22!(25−22)!25!⋅13i22+23!(25−23)!25!⋅12i23+24!(25−24)!25!⋅11i24+25!(25−25)!25!⋅10i25
化简 0!(25−0)!25!⋅125i0:1
化简 1!(25−1)!25!⋅124i1:25i
化简 2!(25−2)!25!⋅123i2:300i2
化简 3!(25−3)!25!⋅122i3:2300i3
化简 4!(25−4)!25!⋅121i4:12650i4
化简 5!(25−5)!25!⋅120i5:53130i5
化简 6!(25−6)!25!⋅119i6:177100i6
化简 7!(25−7)!25!⋅118i7:480700i7
化简 8!(25−8)!25!⋅117i8:1081575i8
化简 9!(25−9)!25!⋅116i9:2042975i9
化简 10!(25−10)!25!⋅115i10:3268760i10
化简 11!(25−11)!25!⋅114i11:4457400i11
化简 12!(25−12)!25!⋅113i12:5200300i12
化简 13!(25−13)!25!⋅112i13:5200300i13
化简 14!(25−14)!25!⋅111i14:4457400i14
化简 15!(25−15)!25!⋅110i15:3268760i15
化简 16!(25−16)!25!⋅19i16:2042975i16
化简 17!(25−17)!25!⋅18i17:1081575i17
化简 18!(25−18)!25!⋅17i18:480700i18
化简 19!(25−19)!25!⋅16i19:177100i19
化简 20!(25−20)!25!⋅15i20:53130i20
化简 21!(25−21)!25!⋅14i21:12650i21
化简 22!(25−22)!25!⋅13i22:2300i22
化简 23!(25−23)!25!⋅12i23:300i23
化简 24!(25−24)!25!⋅11i24:25i24
化简 25!(25−25)!25!⋅10i25:i25
=1+25i+300i2+2300i3+12650i4+53130i5+177100i6+480700i7+1081575i8+2042975i9+3268760i10+4457400i11+5200300i12+5200300i13+4457400i14+3268760i15+2042975i16+1081575i17+480700i18+177100i19+53130i20+12650i21+2300i22+300i23+25i24+i25
化简 1+25i+300i2+2300i3+12650i4+53130i5+177100i6+480700i7+1081575i8+2042975i9+3268760i10+4457400i11+5200300i12+5200300i13+4457400i14+3268760i15+2042975i16+1081575i17+480700i18+177100i19+53130i20+12650i21+2300i22+300i23+25i24+i25:4096i+4096
=4096i+4096
Rewrite in standard complex form: 4096+4096i
=4096+4096i