展开 ((2x-1)^2)/4

解答

展开

\frac{( 2 x - 1 ) ^{2}}{4}

x^{2} - x + \frac{1}{4}

求解步骤

\frac{( 2 x - 1 ) ^{2}}{4}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{4 x ^{2} - 4 x + 1}{4}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 4 x + 1}{4} = \frac{4 x ^{2}}{4} - \frac{4 x}{4} + \frac{1}{4}

= \frac{4 x ^{2}}{4} - \frac{4 x}{4} + \frac{1}{4}

数字相除:

\frac{4}{4} = 1

= x^{2} - x + \frac{1}{4}

e x p an d \frac{1}{s ( s ^{2} + 1 )}

e x p an d (sin (x) + csc (x))^{2}

e x p an d (x + \frac{1}{x})^{2}

e x p an d \frac{1}{( x + 2 ) ^{2}}

e x p an d (e^{x} + e^{- x}) (e^{x} - e^{- x})