展开 (2sin(x)-4)^2

解答

展开

(2 sin (x) - 4)^{2}

4 sin^{2} (x) - 16 sin (x) + 16

求解步骤

(2 sin (x) - 4)^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(2 sin (x) - 4)^{2} = (2 sin (x))^{2} - 2 \cdot 2 sin (x) \cdot 4 + 4^{2}

= (2 sin (x))^{2} - 2 \cdot 2 sin (x) \cdot 4 + 4^{2}

化简

(2 sin (x))^{2} - 2 \cdot 2 sin (x) \cdot 4 + 4^{2} : 4 sin^{2} (x) - 16 sin (x) + 16

= 4 sin^{2} (x) - 16 sin (x) + 16

e x p an d (4 + x) x^{3} e^{4 x} + 5

e x p an d \frac{( x - 1 ) ( y - 1 ) ( z - 1 )}{( a - 1 ) ( b - 1 )}

e x p an d \frac{( - 3 - i ) ^{\frac{1}{3}} - 1}{3}

e x p an d sin (x) (2 sin (x) + 1)

e x p an d \frac{2 ( 31 - 4 10 )}{9}