erweitern |sec(x)+tan(x)|(-sec(x)+tan(x))

Lösung

erweitern

∣ sec (x) + tan (x) ∣ (- sec (x) + tan (x))

- sec (x) ∣ sec (x) + tan (x) ∣ + tan (x) ∣ sec (x) + tan (x) ∣

Schritte zur Lösung

∣ sec (x) + tan (x) ∣ (- sec (x) + tan (x))

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = ∣ sec (x) + tan (x) ∣, b = - sec (x), c = tan (x)

= ∣ sec (x) + tan (x) ∣ (- sec (x)) + ∣ sec (x) + tan (x) ∣ tan (x)

Wende Minus-Plus Regeln an

+ (- a) = - a

= - sec (x) ∣ sec (x) + tan (x) ∣ + tan (x) ∣ sec (x) + tan (x) ∣

e x p an d sin (x) (1 + sec^{2} (x))

e x p an d l im x \Rightarrow - 1 (3 x^{3} - 10) (x + 3)

e x p an d (t + Δ t)^{2}

e x p an d 12 (A e^{4 x} + B e^{- 3 x})

e x p an d \frac{3 ( 3 x + 2 ) ( x + 5 )}{( x - 1 ) ( x - 3 )}