What is expand e^{2x}(2cos(x)-sin(x)) ?

The solution to expand e^{2x}(2cos(x)-sin(x)) is 2e^{2x}cos(x)-e^{2x}sin(x)

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expand e^{2x}(2cos(x)-sin(x))

expand

e^{2 x} (2 cos (x) - sin (x))

2 e^{2 x} cos (x) - e^{2 x} sin (x)

Solution steps

e^{2 x} (2 cos (x) - sin (x))

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 x}, b = 2 cos (x), c = sin (x)

= e^{2 x} \cdot 2 cos (x) - e^{2 x} sin (x)

= 2 e^{2 x} cos (x) - e^{2 x} sin (x)

\frac{3 x ( - x ^{2} - x + 2 )}{2}

(x - cos (y)) d x - sin (y) d y

(1 - tan (θ)) tan (2 θ)

- \frac{2 x ( - x ^{2} + 189 )}{( x ^{2} + 63 ) ^{3}}

(1 + x^{2}) (1 + x^{2})

What is expand e^{2x}(2cos(x)-sin(x)) ?
The solution to expand e^{2x}(2cos(x)-sin(x)) is 2e^{2x}cos(x)-e^{2x}sin(x)