展开 (t-3)\H(t-1)

解答

展开

(t - 3) H (t - 1)

t H (t - 1) - 3 H (t - 1)

求解步骤

(t - 3) H (t - 1)

= H (t - 1) (t - 3)

使用分配律:

a (b - c) = ab - a c

a = H (t - 1), b = t, c = 3

= H (t - 1) t - H (t - 1) \cdot 3

= t H (t - 1) - 3 H (t - 1)

e x p an d \frac{- 2 x ^{2} + 3 x - 24}{( x ^{2} + 9 ) ( x - 2 )}

e x p an d \frac{1}{s ( s + 2 ) ( s + 7 )}

e x p an d \frac{x - 2}{( x - 4 ) ( 3 x + 2 )}

e x p an d \frac{1}{x ^{2} ( x ^{2} + 9 )}

e x p an d (e^{x^{2} - 2 x}) \cdot (2 x - 2)