deg2rad [((w^2-3)(4w+2))/(w+1)]^'

Lösung

grad in radianten

[\frac{( w ^{2} - 3 ) ( 4 w + 2 )}{w + 1}]^{^{'}}

\frac{π}{180} (\frac{( w ^{2} - 3 ) ( 4 w + 2 )}{w + 1})^{'}

Schritte zur Lösung

[\frac{( w ^{2} - 3 ) ( 4 w + 2 )}{w + 1}]^{^{'}}

Um von Grad in Radiant zu konvertieren, multipliziere die Gradzahl mit

\frac{π}{18 0 ^{\circ}}

= [\frac{( w ^{2} - 3 ) ( 4 w + 2 )}{w + 1}]^{^{^{'}}} \cdot \frac{π}{18 0 ^{\circ}}

Vereinfache

= \frac{π}{180} (\frac{( w ^{2} - 3 ) ( 4 w + 2 )}{w + 1})^{^{^{'}}}

e x p an d \frac{2 x}{( x ^{2} - 4 ) ^{2}}

e x p an d (a - λ) (b - λ) (c - λ) (d - λ) (e - λ)

e x p an d (sin (θ) - 2 r cos^{2} (θ)) d r + r cos (θ) (2 r sin (θ) + 1) d θ

e x p an d \frac{z ^{2} - 6 z + 8}{( z + 1 ) ( z + 2 )}

e x p an d 8 \cdot 6