erweitern (2(x+h)^3)/3

Lösung

erweitern

\frac{2 ( x + h ) ^{3}}{3}

\frac{2 x ^{3}}{3} + 2 x^{2} h + 2 x h^{2} + \frac{2 h ^{3}}{3}

Schritte zur Lösung

\frac{2 ( x + h ) ^{3}}{3}

(x + h)^{3} = x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3}

= \frac{2 ( x ^{3} + 3 x ^{2} h + 3 x h ^{2} + h ^{3} )}{3}

Multipliziere aus

2 (x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3}) : 2 x^{3} + 6 x^{2} h + 6 x h^{2} + 2 h^{3}

= \frac{2 x ^{3} + 6 x ^{2} h + 6 x h ^{2} + 2 h ^{3}}{3}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{3} + 6 x ^{2} h + 6 x h ^{2} + 2 h ^{3}}{3} = \frac{2 x ^{3}}{3} + \frac{6 x ^{2} h}{3} + \frac{6 x h ^{2}}{3} + \frac{2 h ^{3}}{3}

= \frac{2 x ^{3}}{3} + \frac{6 x ^{2} h}{3} + \frac{6 x h ^{2}}{3} + \frac{2 h ^{3}}{3}

Teile die Zahlen:

\frac{6}{3} = 2

= \frac{2 x ^{3}}{3} + 2 x^{2} h + 2 x h^{2} + \frac{2 h ^{3}}{3}

e x p an d \frac{( x + 1 ) ( x - 1 )}{x + 4}

e x p an d (x + 1) \times ln^{2} (x + 1)

e x p an d sec (2 (arcsec (\frac{25}{7}) + 2 πn))

e x p an d \frac{( x + 1 ) ( x - 1 )}{x + 2}

e x p an d e^{x - 5} (x - 1)^{2}