erweitern ((k+1)(3k+2))/2

Lösung

erweitern

\frac{( k + 1 ) ( 3 k + 2 )}{2}

\frac{3 k ^{2}}{2} + \frac{5 k}{2} + 1

Schritte zur Lösung

\frac{( k + 1 ) ( 3 k + 2 )}{2}

Multipliziere aus

(k + 1) (3 k + 2) : 3 k^{2} + 5 k + 2

= \frac{3 k ^{2} + 5 k + 2}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 k ^{2} + 5 k + 2}{2} = \frac{3 k ^{2}}{2} + \frac{5 k}{2} + \frac{2}{2}

= \frac{3 k ^{2}}{2} + \frac{5 k}{2} + \frac{2}{2}

Wende Regel an

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{3 k ^{2}}{2} + \frac{5 k}{2} + 1

e x p an d (5 + 7)^{4}

e x p an d \frac{k ( k + 1 ) ( 2 k + 1 )}{6}

e x p an d \frac{x - 4 \cdot x + 4}{( x - 2 ) ( x - 4 )}

e x p an d \frac{6 x ^{2} + 7 x + 9}{3 x}

e x p an d \frac{( a - x ) ^{4}}{4}