展开 ((2y-1)^2)/4

解答

展开

\frac{( 2 y - 1 ) ^{2}}{4}

y^{2} - y + \frac{1}{4}

求解步骤

\frac{( 2 y - 1 ) ^{2}}{4}

(2 y - 1)^{2} = 4 y^{2} - 4 y + 1

= \frac{4 y ^{2} - 4 y + 1}{4}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 y ^{2} - 4 y + 1}{4} = \frac{4 y ^{2}}{4} - \frac{4 y}{4} + \frac{1}{4}

= \frac{4 y ^{2}}{4} - \frac{4 y}{4} + \frac{1}{4}

数字相除:

\frac{4}{4} = 1

= y^{2} - y + \frac{1}{4}

e x p an d (sin (x) + 2)^{3}

s im pl i f y (x + i y)^{3} + 2 i (x + i y)^{2} + 5 (x + i y) + 2

s im pl i f y 2 (x + 2)

e x p an d y (x^{2} + y^{2} - 1) d x + x (x^{2} + y^{2} + 1) d y

e x p an d \frac{( x + 2 ) ( 4 x - 1 ) ^{2}}{x ^{3}}