展开 (1-e^t)^2

解答

展开

(1 - e^{t})^{2}

1 - 2 e^{t} + e^{2 t}

求解步骤

(1 - e^{t})^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 1, b = e^{t}

= 1^{2} - 2 \cdot 1 \cdot e^{t} + (e^{t})^{2}

化简

1^{2} - 2 \cdot 1 \cdot e^{t} + (e^{t})^{2} : 1 - 2 e^{t} + e^{2 t}

= 1 - 2 e^{t} + e^{2 t}

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