展开 n^{1/2}(n^{3/2}+n+5)

解答

展开

n^{\frac{1}{2}} (n^{\frac{3}{2}} + n + 5)

n^{2} + n^{\frac{3}{2}} + n^{\frac{1}{2}} \cdot 5

求解步骤

n^{\frac{1}{2}} (n^{\frac{3}{2}} + n + 5)

使用分配律:

m (a + b + c) = ma + mb + m c

n^{\frac{1}{2}} (n^{\frac{3}{2}} + n + 5) = n^{\frac{1}{2}} n^{\frac{3}{2}} + n^{\frac{1}{2}} n + n^{\frac{1}{2}} \cdot 5

= n^{\frac{1}{2}} n^{\frac{3}{2}} + n^{\frac{1}{2}} n + n^{\frac{1}{2}} \cdot 5

n^{\frac{1}{2}} n^{\frac{3}{2}} = n^{2}

n^{\frac{1}{2}} n = n^{\frac{3}{2}}

= n^{2} + n^{\frac{3}{2}} + n^{\frac{1}{2}} \cdot 5

e x p an d lo g_{7} (x) (5 y (3 y + 4))

e x p an d (y - x y^{'} (x))^{3}

e x p an d \frac{4 x ^{5} + 2 x ^{4} - 4 x ^{3}}{( x + 1 ) ^{2}}

e x p an d - 2

e x p an d \frac{1}{3} (2 - x)^{3}