展开-(x+2)sqrt(-(x+1)(x-1))

解答

展开

- (x + 2) - (x + 1) (x - 1)

- x - x^{2} + 1 - 2 - x^{2} + 1

求解步骤

- (x + 2) - (x + 1) (x - 1)

= - - (x + 1) (x - 1) (x + 2)

使用分配律:

a (b + c) = ab + a c

- - (x + 1) (x - 1) (x + 2) = - - (x + 1) (x - 1) x - - (x + 1) (x - 1) \cdot 2

= - - (x + 1) (x - 1) x - - (x + 1) (x - 1) \cdot 2

化简

- - (x + 1) (x - 1) x - - (x + 1) (x - 1) \cdot 2 : - x - x^{2} + 1 - 2 - x^{2} + 1

= - x - x^{2} + 1 - 2 - x^{2} + 1

e x p an d - 3 (6 x + 2 y = 14, 0) 6 (3 x + 5 y = 131)

e x p an d in t er v a l s (x^{2} + x - 2)^{6}

e x p an d \frac{( x ^{3} + y ^{3} + z ^{3} ) ( x y + x z + yz )}{x yz ( x ^{2} + y ^{2} + z ^{2} )}

e x p an d \frac{1}{( - 1 - s ) ^{2}}

e x p an d \frac{1}{2} (- \frac{ln ( x )}{5 x ^{5}} - \frac{1}{25 x ^{5}})