展開する (3sin(x)+2cos(x))^2+(2sin(x)-3cos(x))

解

展開する

(3 sin (x) + 2 cos (x))^{2} + (2 sin (x) - 3 cos (x))

9 sin^{2} (x) + 12 cos (x) sin (x) + 4 cos^{2} (x) + 2 sin (x) - 3 cos (x)

解答ステップ

(3 sin (x) + 2 cos (x))^{2} + (2 sin (x) - 3 cos (x))

規則を適用する:

a + (b + c) = a + b + c

(3 sin (x) + 2 cos (x))^{2} + (2 sin (x) - 3 cos (x)) = (3 sin (x) + 2 cos (x))^{2} + 2 sin (x) - 3 cos (x)

= (3 sin (x) + 2 cos (x))^{2} + 2 sin (x) - 3 cos (x)

拡張

(3 sin (x) + 2 cos (x))^{2} : 9 sin^{2} (x) + 12 cos (x) sin (x) + 4 cos^{2} (x)

= 9 sin^{2} (x) + 12 cos (x) sin (x) + 4 cos^{2} (x) + 2 sin (x) - 3 cos (x)