展开 ((715-p)^2)/(10)

解答

展开

\frac{( 715 - p ) ^{2}}{10}

\frac{p ^{2}}{10} - 143 p + \frac{102245}{2}

求解步骤

\frac{( 715 - p ) ^{2}}{10}

(715 - p)^{2} = 511225 - 1430 p + p^{2}

= \frac{511225 - 1430 p + p ^{2}}{10}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{511225 - 1430 p + p ^{2}}{10} = \frac{511225}{10} - \frac{1430 p}{10} + \frac{p ^{2}}{10}

= \frac{511225}{10} - \frac{1430 p}{10} + \frac{p ^{2}}{10}

消掉

\frac{511225}{10} : \frac{102245}{2}

= \frac{102245}{2} - \frac{1430 p}{10} + \frac{p ^{2}}{10}

数字相除:

\frac{1430}{10} = 143

= \frac{102245}{2} - 143 p + \frac{p ^{2}}{10}

改写为标准形式

= \frac{p ^{2}}{10} - 143 p + \frac{102245}{2}

e x p an d \frac{( 2 + i ) ^{9}}{( 1 - 2 i ) ^{8}}

e x p an d (x^{2} - x + 1) (e^{x})

e x p an d \frac{3 x ^{2} + 10 x + 3}{( x + 1 ) ^{2} ( x + 2 ) ( x ^{2} + 1 )}

s im pl i f y (5 x + 16 + 4)^{2}

s im pl i f y \frac{1}{2} (0.5 \cdot 20 + 1) + \frac{1}{2} (0.5 \cdot 5 + 1)