4x^2+10x-5=0

解答

4 x^{2} + 10 x - 5 = 0

x = \frac{- 5 + 3 5}{4}, x = - \frac{5 + 3 5}{4}

十进制

x = 0.42705 \dots, x = - 2.92705 \dots

求解步骤

4 x^{2} + 10 x - 5 = 0

使用求根公式求解

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

1 0^{2} - 4 \cdot 4 (- 5) = 65

x_{1, 2} = \frac{- 10 \pm 6 5}{2 \cdot 4}

将解分隔开

x_{1} = \frac{- 10 + 6 5}{2 \cdot 4}, x_{2} = \frac{- 10 - 6 5}{2 \cdot 4}

x = \frac{- 10 + 6 5}{2 \cdot 4} : \frac{- 5 + 3 5}{4}

x = \frac{- 10 - 6 5}{2 \cdot 4} : - \frac{5 + 3 5}{4}

二次方程组的解是:

x = \frac{- 5 + 3 5}{4}, x = - \frac{5 + 3 5}{4}

12 t - 2 < - 5 t + 3612 t - 2 < - 5 t + 36

- 5 (4 x - 4) - 2 x - 4 = - 28

\frac{5 x ( x - 3 )}{2} = 3 (x - 5) + 6

f a c t or 2 j^{2} + 11 j + 12

f a c t or 5 x z - 5 yz - x + y