展开 (x^3+2x^2+10x+18)/((x^2+9)(x^2+1)(x+1))

解答

展开

\frac{x ^{3} + 2 x ^{2} + 10 x + 18}{( x ^{2} + 9 ) ( x ^{2} + 1 ) ( x + 1 )}

\frac{x ^{3} + 2 x ^{2} + 10 x + 18}{x ^{5} + x ^{4} + 10 x ^{3} + 10 x ^{2} + 9 x + 9}

求解步骤

\frac{x ^{3} + 2 x ^{2} + 10 x + 18}{( x ^{2} + 9 ) ( x ^{2} + 1 ) ( x + 1 )}

乘开

(x^{2} + 9) (x^{2} + 1) (x + 1) : x^{5} + x^{4} + 10 x^{3} + 10 x^{2} + 9 x + 9

= \frac{x ^{3} + 2 x ^{2} + 10 x + 18}{x ^{5} + x ^{4} + 10 x ^{3} + 10 x ^{2} + 9 x + 9}

e x p an d (\frac{1}{2} x^{3} y^{2} - 4 y)^{9}

e x p an d A (- 2, 5) B (7, - 3)

e x p an d (4 x^{\frac{1}{2}} + 6 x^{\frac{3}{2}}) (3 x - 9)

e x p an d \frac{2 ( 2 z + 1 )}{4 z + 1}

e x p an d (3 - x) (\frac{1}{3} + \frac{2}{27} x^{2} + \frac{2}{81} x^{3})