展開する d/d (2xy^2-3x^2y=6x)

解

展開する

\frac{d}{d} (2 x y^{2} - 3 x^{2} y = 6 x)

2 x y^{2} - 3 x^{2} y = 6 x

解答ステップ

\frac{d}{d} (2 x y^{2} - 3 x^{2} y = 6 x)

= \frac{d}{d} (2 x y^{2} - 3 \cdot 6 = x^{2} x y)

分配法則を適用する:

a (b - c) = ab - a c

a = \frac{d}{d}, b = 2 x y^{2}, c = 3 x^{2} y = 6 x

\frac{d}{d} \cdot 2 x y^{2} - \frac{d}{d} \cdot 3 x^{2} y = 6 x

2 \cdot \frac{d}{d} x y^{2} - 3 \cdot \frac{d}{d} x^{2} y = 6 x

拡張

2 \cdot \frac{d}{d} x y^{2} - 3 \cdot \frac{d}{d} x^{2} y : 2 x y^{2} - 3 x^{2} y

2 x y^{2} - 3 x^{2} y = 6 x