展开 (x^4+x^2+16x-12)/(x^3(x-2)^2)

解答

展开

\frac{x ^{4} + x ^{2} + 16 x - 12}{x ^{3} ( x - 2 ) ^{2}}

\frac{x ^{4} + x ^{2} + 16 x - 12}{x ^{5} - 4 x ^{4} + 4 x ^{3}}

求解步骤

\frac{x ^{4} + x ^{2} + 16 x - 12}{x ^{3} ( x - 2 ) ^{2}}

(x - 2)^{2} = x^{2} - 4 x + 4

= \frac{x ^{4} + x ^{2} + 16 x - 12}{x ^{3} ( x ^{2} - 4 x + 4 )}

乘开

x^{3} (x^{2} - 4 x + 4) : x^{5} - 4 x^{4} + 4 x^{3}

= \frac{x ^{4} + x ^{2} + 16 x - 12}{x ^{5} - 4 x ^{4} + 4 x ^{3}}

e x p an d (\frac{2.6}{4} x^{π} + \frac{2.2}{6.8} y^{e})^{16}

e x p an d x (x + 7) 11 d x

e x p an d 4 e^{x} (x^{2} - 49)

e x p an d \frac{e ^{- s} - e ^{- 5 s} + ( e ^{- s} + 4 e ^{- 5 s} ) s + 2 s ^{2}}{s ^{2} ( s ^{2} + 5 s + 6 )}

e x p an d (y^{2} + 5 x^{3}) \frac{d}{d x} (+ x y)