展开 sqrt((1)^2+(2t)^2+(3t^2)^2)

解答

展开

(1)^{2} + (2 t)^{2} + (3 t^{2})^{2}

1 + 4 t^{2} + 9 t^{4}

求解步骤

1^{2} + (2 t)^{2} + (3 t^{2})^{2}

使用法则

1^{a} = 1

1^{2} = 1

= 1 + (2 t)^{2} + (3 t^{2})^{2}

(2 t)^{2} = 2^{2} t^{2}

(3 t^{2})^{2} = 3^{2} t^{4}

= 1 + 2^{2} t^{2} + 3^{2} t^{4}

整理后得

= 1 + 4 t^{2} + 9 t^{4}

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