展开 (5sec(θ)+2)^2

解答

展开

(5 sec (θ) + 2)^{2}

25 sec^{2} (θ) + 20 sec (θ) + 4

求解步骤

(5 sec (θ) + 2)^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(5 sec (θ) + 2)^{2} = (5 sec (θ))^{2} + 2 \cdot 5 sec (θ) \cdot 2 + 2^{2}

= (5 sec (θ))^{2} + 2 \cdot 5 sec (θ) \cdot 2 + 2^{2}

化简

(5 sec (θ))^{2} + 2 \cdot 5 sec (θ) \cdot 2 + 2^{2} : 25 sec^{2} (θ) + 20 sec (θ) + 4

= 25 sec^{2} (θ) + 20 sec (θ) + 4

e x p an d lo g_{10} (3) (x + 2)

e x p an d \frac{( x - 1 ) ( x - 2 ) ( x - 3 )}{( 0 - 1 ) ( 0 - 2 ) ( 0 - 3 )}

e x p an d e^{a} + e^{a} (x - a)

e x p an d (1 + cos (α)) (1 + csc (α))

e x p an d (a + b x + 2 c x^{2} + 3 d x^{3} + 4 e x^{4})^{2}