展开 (1-e^{-c})^2

解答

展开

(1 - e^{- c})^{2}

1 - 2 e^{- c} + e^{- 2 c}

求解步骤

(1 - e^{- c})^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 1, b = e^{- c}

= 1^{2} - 2 \cdot 1 \cdot e^{- c} + (e^{- c})^{2}

化简

1^{2} - 2 \cdot 1 \cdot e^{- c} + (e^{- c})^{2} : 1 - 2 e^{- c} + e^{- 2 c}

= 1 - 2 e^{- c} + e^{- 2 c}

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