u^2-3u+2=0

解

u^{2} - 3 u + 2 = 0

u = 2, u = 1

解答ステップ

u^{2} - 3 u + 2 = 0

解くとthe二次式

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

u_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

解を分離する

u_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, u_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

u = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

u = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

二次equationの解:

u = 2, u = 1