-25t^2+200t+375=0

解

- 25 t^{2} + 200 t + 375 = 0

t = 4 - 31, t = 4 + 31

十進法表記

t = - 1.56776 \dots, t = 9.56776 \dots

解答ステップ

- 25 t^{2} + 200 t + 375 = 0

解くとthe二次式

t_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 ( - 25 ) \cdot 375}{2 ( - 25 )}

20 0^{2} - 4 (- 25) \cdot 375 = 5031

t_{1, 2} = \frac{- 200 \pm 50 31}{2 ( - 25 )}

解を分離する

t_{1} = \frac{- 200 + 50 31}{2 ( - 25 )}, t_{2} = \frac{- 200 - 50 31}{2 ( - 25 )}

t = \frac{- 200 + 50 31}{2 ( - 25 )} : 4 - 31

t = \frac{- 200 - 50 31}{2 ( - 25 )} : 4 + 31

二次equationの解:

t = 4 - 31, t = 4 + 31