vereinfachen (1+1/6(4260.4403))^{-0.5}100

Lösung

vereinfachen

(1 + \frac{1}{6} \cdot (4260.4403))^{- 0.5} \cdot 100

\frac{10000 6}{42664403}

Dezimale

3.75009 \dots

Schritte zur Lösung

(1 + \frac{1}{6} (4260.4403))^{- 0.5} \cdot 100

Apply rule:

(a) = a

(4260.4403) = 4260.4403

= (1 + \frac{1}{6} \cdot 4260.4403)^{- 0.5} \cdot 100

Wende Exponentenregel an:

a^{- b} = \frac{1}{a ^{b}}

(1 + \frac{1}{6} \cdot 4260.4403)^{- 0.5} = \frac{1}{( 1 + \frac{1}{6} \cdot 4260.4403 ) ^{0.5}}

= \frac{1}{( 1 + \frac{1}{6} \cdot 4260.4403 ) ^{0.5}} \cdot 100

(1 + \frac{1}{6} \cdot 4260.4403)^{0.5} = \frac{4266440 3 ^{\frac{1}{2}}}{100 6}

= \frac{1}{\frac{4266440 3 ^{\frac{1}{2}}}{100 6}} \cdot 100

Wende Bruchregel an:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{100 6}{4266440 3 ^{\frac{1}{2}}} \cdot 100

\frac{100 6}{4266440 3 ^{\frac{1}{2}}} \cdot 100 = \frac{10000 6}{4266440 3 ^{\frac{1}{2}}}

= \frac{10000 6}{4266440 3 ^{\frac{1}{2}}}

Wende Exponentenregel an:

a^{\frac{1}{2}} = a

4266440 3^{\frac{1}{2}} = 42664403

= \frac{10000 6}{42664403}

e x p an d (3 x)^{2}

s im pl i f y 3 (e^{2 t})^{2} t \cdot e^{2 t}

s im pl i f y e^{8}

s im pl i f y (2 y) (3 y)

s im pl i f y e^{- 0.5} \cdot 0.5