|2x+3|=1

Lösung

∣ 2 x + 3 ∣ = 1

x = - 2 or x = - 1

Schritte zur Lösung

∣ 2 x + 3 ∣ = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

2 x + 3 = - 1 or 2 x + 3 = 1

2 x + 3 = - 1 or 2 x + 3 = 1

x = - 2 or x = - 1

x^{2} = 343

- x^{2} + 4 x + 5 > 0

s im pl i f y 3750

s im pl i f y 3 a + 4 c - 2 a [3 (4 - b)] + 3 c + 3

- 4 lo g_{5} (x - 5) \geq 3